Questions
A block of mass m is placed on another blocks of mass M which itself is lying on a horizontal surface. The coefficient of friction between the two blocks is
µ1 and that between the block of mass M and horizontal surface is pr. What maximum horizontal force can be applied to the lower block so that the two blocks move without separation ?
detailed solution
Correct option is D
Here the force applied should be such that the force on block of mass m should not exceed from the force of friction (µ1 m g). Let the system move with accelerationa. ThenF−μ2(M+m)g=(M+m)a …(1)For block of mass m,F1=ma=μ1mg or a=μ1g …(2)From eqs. (1) and (2), we getF=μ2(M+m)g+(M+m)μ1g =(M+m)g(μ1+μ2)Talk to our academic expert!
Similar Questions
A 4 kg block A is placed at the top of 8 kg block B which rests on a smooth table. A just slips on B when a force of 20 N is applied on A. The maximum horizontal force F required to make both A & B move together is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests