First slide
Two block problem
Question

A block of mass m is placed on another blocks of mass M which itself is lying on a horizontal surface. The coefficient of friction between the two blocks is

µ1 and that between the block of mass M and horizontal surface is pr. What maximum horizontal force can be applied to the lower block so that the two blocks move without separation ?

Moderate
Solution

Here the force applied should be such that the force on block of mass m should not exceed from the force of friction (µ1 m g). Let the system move with acceleration
a. Then

Fμ2(M+m)g=(M+m)a   …(1)

For block of mass m,

F1=ma=μ1mg  or  a=μ1g   …(2)

From eqs. (1) and (2), we get

F=μ2(M+m)g+(M+m)μ1g =(M+m)g(μ1+μ2)

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App