A block of mass m is placed in contact with one end of a smooth tube of mass M. A horizontal force F acts on the tube in each case (i) and (ii). Then

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am=0 and aM=FM in (i)

am=aM=FM+m in (i)

am=aM=FM+m in (ii)

Force on m is mFM+m in (ii)

answer is A.

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Detailed Solution

In first case, m will remain at rest. aM=F/MIn second case, both will accelerate am=aM=F/(M+m)In second case, force on m=mam=mF/(M+m)

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