First slide

Kinetic friction

Question

A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for $μ = 0.2$ is:

Moderate

A

2 $m / s^{2}$
B

3 $m / s^{2}$
C

dependent on the mass rn
D

none of these

Solution

If block does not slide w.r.t platform
F = ma--------- (i)
But $f \leq μN$ ------- (ii)
From (i) and (ii), $ma \leq μ mg$
$a \leq μg$
Hence maximum acceleration of the plank is
0.2 x10 = 2 $m / s^{2}$ .
******* $a_{m a x} = μ_{s} g = 0.2 \times 10 = 2 m s^{- 2}$

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