Q.
A block of mass m is placed on a smooth inclined wedge A B C of inclination θ as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and θ for the block to remain stationary on the wedge is
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a
a=gcosecθ
b
a=gsinθ
c
a=gcosθ
d
a=gtanθ
answer is D.
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Detailed Solution
In non-inertial frame,Nsinθ=ma ........(i)Ncosθ=mg .........(ii)From (i) and (ii),tanθ=aga=gtanθ
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