Q.

A block of mass m is placed on a smooth inclined wedge A B C of inclination θ as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and θ for the block to remain stationary on the wedge is

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a

a=gcosecθ

b

a=gsinθ

c

a=gcosθ

d

a=gtanθ

answer is D.

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Detailed Solution

In non-inertial frame,Nsinθ=ma             ........(i)Ncosθ=mg            .........(ii)From (i) and (ii),tanθ=aga=gtanθ
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