A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g$$ is acceleration due to $$gravity) will be

Question

A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g$$ is acceleration due to $$gravity) will be

Infinity Learn · Accepted Answer

When the whole system is accelerated towards left, then pseudo force (ma) works on a block towards right.For the condition of equilibrium:mgsin⁡θ$$=macos$$⁡θ⇒ $$a=gsin$$⁡θ$$cos$$⁡θTherefore, force exerted by the wedge on the $$blockN=mgcos$$⁡θ$$+masin$$⁡θ$$=mgcos$$⁡θ$$+mgsin$$⁡θ$$cos$$⁡θ$$sin$$⁡θ$$=mgcos2$$⁡θ$$+sin2$$⁡θ$$cos$$⁡θ$$=mgcos$$⁡θ

A block of mass m is placed on a smooth wedge of inclination $θ$ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

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A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

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A block of mass m is placed on a smooth wedge of inclination $θ$ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be