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A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

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a

mg cosθ

b

mg sinθ

c

mg

d

mgcosθ

answer is D.

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Detailed Solution

if it is not falling down component of pseudo force ma cosθ will balence mgsinθ a= g tanθ force given by the wedge mg cosθ + ma sinθ =mgcosθ+m gtanθsinθ on simplifying mgcosθdig

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