A block of mass m is placed on a wedge of mass 2m which rests on a rough horizontal surface. There is no friction between the block and the wedge. Theminimum coefficient of friction between the wedge and the ground so that the wedge does not move is
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a
0.167
b
0.20
c
0.23
d
0.33
answer is B.
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Detailed Solution
Normal reaction exerted by the block on the wedge N = mg cos 450=mg/2Normal reaction exerted by the wedge on the ground N'=(2mg+mg/2 cos 450)=2.5 mgTherefore μmin=N sin 4502mg+N cos 450=0.2