A block of mass m is placed on a wedge of mass $$2$$ m which rests on a rough horizontal surface. There is no friction between the block and the wedge. The minimum coefficient of friction between the wedge and the ground, so that the wedge does not move, is

Question

Infinity Learn · Accepted Answer

For block,  $$a=gsin$$θ$$=g2aH=aV=acos45$$°     $$=g2$$×$$12=g2N2=mg2$$                    ……..(i)mg-N2=mg2$$              ……..$$(ii)For$$ wedge,N'$$=N2+2mg$$              ……..$$(iii)μN'$$=N2$$                      …….$$(iv)Solving$$ above four equations, we getμ $$=0.2$$

A block of mass m is placed on a wedge of mass 2 m which rests on a rough horizontal surface. There is no friction between the block and the wedge. The minimum coefficient of friction between the wedge and the ground, so that the wedge does not move, is

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