A block of mass m is pulled along a horizontal surface by applying a force at an angle θ with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is μ, then the work done by the applied force is
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a
μmgdcosθ+μsinθ
b
μmgdcosθcosθ+μsinθ
c
μmgdsinθcosθ+μsinθ
d
μmgdcosθcosθ-μsinθ
answer is B.
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Detailed Solution
Normal force on the block, N=mg-FsinθBlock moves with uniform velocity. Hence, net force = 0or Fcosθ=μN=μ(mg-Fsinθ)∴ F=μmgcosθ+μsinθW=Fscosθ=μmgdcosθcosθ+μsinθ