First slide
Work done by Diff type of forces
Question

A block of mass m is pulled along a horizontal surface by applying a force at an angle θ with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is μ, then the work done by the applied force is

Moderate
Solution

Normal force on the block,   N=mg-Fsinθ

Block moves with uniform velocity. Hence, net force = 0

or   Fcosθ=μN=μ(mg-Fsinθ)

  F=μmgcosθ+μsinθ

W=Fscosθ=μmgdcosθcosθ+μsinθ

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