A block of mass m is at rest on an inclined plane which is making angle θ with the horizontal. The coefficient of friction between the block and plane is μ. Then, frictional force acting between the surfaces is
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a
μ mg
b
μ mg sin θ
c
μ (mg sin θ - mg cos θ)
d
mg sin θ
answer is D.
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Detailed Solution
The block of mass m is at rest on an inclined plane. Hence, frictional force acting between the surfaces isf=mgsinθ