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Questions  

A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of rnass m2 is suspended. The coefficient of kinetic friction between the block and table is μk When the block A is sliding on the table, the tension in the string is

 

a
(m2+μkm1g)(m1+m2)
b
(m2-μkm1)g(m1+m2)
c
m1m2(1+μk)g(m1+m2)
d
m1m2(1-μs)g(m1+m2)

detailed solution

Correct option is C

T-μkm1g = m1a--------(i)m2g-T = m2a-----(ii)T-μkm1g = m1(m2g-T)m2T = m1m2g(μk+1)(m1+m2)

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