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Q.

A block of mass M rests on a table. It is fastened to the lower end of a light, vertical spring. The upper end of the spring is fastened to a block of mass m. The upper block is pushed down by an additional force 3mg, so the spring compression is 4 mg/k. In this configuration, the upper block is released from rest. The spring lifts the lower block off the table. what is the greatest possible value for Mm?

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answer is 2.

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Detailed Solution

If the spring is just barely able to lift the lower block from the table, the spring lifts it through no noticeable distance, but exerts on the block a force equal to its weight Mg. The extension of the spring, from F→s=kx, must be mg/k Between an initial point at release and a final point when the moving block first comes to rest, we have Ki+Ugi+Usi=Kf+Ugf+Usf0+mg−4mgk+12k4mgk2=0+mgMgk+12kMgk2−4m2g2k+8m2g2k=mMg2k+M2g22k4m2=mM+M22M22+mM−4m2=0M=−m±m2−412−4m2212=−m±9m2Only a positive mass is physical, so we takeM=m(3−1)=2m Hence, Mm=2.
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