A block A of mass M rests on a wedge B of mass 2M and inclination θ. There is sufficient friction between A and B, so that A does not slip on B. If there is no friction between B and ground, the compression in spring is
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a
Mgcosθk
b
Mgcosθsinθk
c
Mgsinθk
d
zero
answer is D.
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Detailed Solution
On M, horizontal components of N and f are balanced (as Mg is vertical). Hence, on 2M also, they will be balanced.∴ Horizontal force kx on 2M should be zero.