A block of mass m is revolving in a smooth horizontal plane with a constant speed v. If the radius of the circular path is R, find the total contact force received by the block.

FBD: Let N1 N2 ↑be the normal reactions offered by the vertical and horizontal surfaces respectively. N1 pushes the block towards the centre of circle and N2 equilibrate the block in vertical by nullifying the weight.Force equation:N1=mar=mv2R   ......(i)N2=mg              .......(ii)Hence, the net reaction (contact) force is N→=N→1+N→2     |N→|=N→1+N→2=N22+N12Substituting N1 and N2, we haveN=mv4R2+g2