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Q.

A block of mass m slides down an inclined plane which makes an angle θ with the horizontal. The coefficient of friction between the block and the plane is μ . The force exerted by the block on the plane is

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a

mg cos θ

b

μ2+1.mgcosθ

c

μ mg cos θμ2+1

d

μ mg cos θ

answer is B.

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Detailed Solution

fk= μ mg cos θ,   N = mg cos θ,    R = fk2+N2
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