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A block of mass M is suspended by a spring and allowed to oscillate vertically with time period 1 second wen another block of mass m is attached to the block of mass M and allowed to oscillate vertically, the time period is found to be 2 sec then, M/m is equal to 

a
3
b
1/2
c
1/3
d
2

detailed solution

Correct option is C

2πMK=T1 and 2πM+mK=T2∴ M+mM=T2T1⇒mM=(T2T1)2−1=(2)2−1=3⇒Mm=13

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