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A block of mass M is suspended from a light spring of force constant k. Another mass m moving upwards with velocity v hits the mass M and gets embedded in it. What will be the amplitude of oscillation of the combined mass ?

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a

mv(M−m)k

b

mv(M+m)k

c

Mv(M−m)k

d

MV(M+m)k

answer is B.

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Detailed Solution

mv=(M+m)v′ or v′=mM+mv Further, maximum P.E. = maximum K.E. ∴ 12kA2=12(M+m)v′2 or A=M+mk1/2×V′ =M+mk1/2×mM+m×V=mv(M+m)k

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