A block of mass m and wedge M is arranged as shown in the figure.
Initially the system is kept stationary, certain time system is released from rest. If acceleration of M is found to be $A = \sqrt{5} m / s^{2}$ towards right, then find net acceleration of m with respect to ground

Question

A block of mass m and wedge M is arranged as shown in the figure.

Initially the system is kept stationary, certain time system is released from rest. If acceleration of M is found to be $A = \sqrt{5} m / s^{2}$ towards right, then find net acceleration of m with respect to ground

Infinity Learn · Accepted Answer

If system is released, the wedge will slide towards right. Let wedge slide towards right by distance .r. The string of length $$3x$$ will be adjusted on the inclined face. Let  dwedge $$=x$$ (towards$$ $$right)  Hence  dblock, wedge $$=3xd$$→block $$=d$$→block, wedge $$+d$$→wedge $$=(3x)2+x2+2(3x)(x)$$$$cos$$⁡$$180$$−$$37$$∘$$=10x2$$−$$6x2cos$$⁡$$37$$∘$$=x10$$−$$6cos$$⁡$$37$$∘$$=x10$$−$$6$$×$$45=x265Hence$$, acceleration of blocka→$$m=A265=26m/s2$$

A block of mass m and wedge M is arranged as shown in the figure.
Initially the system is kept stationary, certain time system is released from rest. If acceleration of M is found to be $A = \sqrt{5} m / s^{2}$ towards right, then find net acceleration of m with respect to ground

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A block of mass m and wedge M is arranged as shown in the figure.Initially the system is kept stationary, certain time system is released from rest. If acceleration of M is found to be A=5m/s2 towards right, then find net acceleration of m with respect to ground

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A block of mass m and wedge M is arranged as shown in the figure.
Initially the system is kept stationary, certain time system is released from rest. If acceleration of M is found to be $A = \sqrt{5} m / s^{2}$ towards right, then find net acceleration of m with respect to ground