A block is placed on a frictionless horizontal table. The mass of the block is m and springs are attached on either side with force constants K1 and K2 . If the block is displaced a little and left to oscillate, then the angular frequency of oscillation will be

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K1+K2m1/2

K1K2m(K1+K2)1/2

K1K2(K1−K2)m1/2

K12+K22(K1+K2)m1/2

answer is A.

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Detailed Solution

In this case springs are in parallel, so keq=k1+k2and ω=keqm=k1+k2m

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