Questions
A block placed on a horizontal surface is being pushed by a force F making an angle with the vertical. The coefficient of friction between block and surface is . The force required to slide the block with uniform velocity on the floor is:
detailed solution
Correct option is A
For vertical equilibrium of the block: R = F cos θ + mg-------------(i)While for horizontal: F sin θ = μR-----------(ii)From (i) and (ii),F sin θ = μ(F cos θ + mg)or F = μmg(sin θ - μ cos θ)Talk to our academic expert!
Similar Questions
A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. The magnitude of the force acting upwards at an angle of 60° from the horizontal that will just start the block moving is
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