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Q.

A block placed on a horizontal surface is being pushed by a force F making an angle θ with the vertical. The coefficient of friction between block and surface is μ. The force required to slide the block with uniform velocity on the floor is:

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a

μmg(sin θ-μ cos θ)

b

(sin θ - μ cos θ)μmg

c

μmg

d

none of these

answer is A.

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Detailed Solution

For vertical equilibrium of the block:  R = F cos θ + mg-------------(i)While for horizontal:    F sin θ = μR-----------(ii)From (i) and (ii),F sin θ = μ(F cos θ + mg)or F = μmg(sin θ - μ cos θ)
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