First slide

Pseudo force

Question

A block is placed on the top of a smooth inclined plane of inclination $θ$ kept on the floor of a lift. When the lift is descending with a retardation a, the block is released. The acceleration of the block relative to the incline is

Moderate

A

g sin $θ$
B

a sin $θ$
C

$(g - a)$ sin $θ$
D

$(g + a)$ sin $θ$

Solution

Since the lift is accelerating downward , vertically upward pseudo force ma will be acting on the block and hence resultant force acting on the block along the incline relative to the lift is $m (g - a) \sin θ .$
Hence, the acceleration of the block relative to the incline is $(g - a)$ sin $θ$ .

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