A block pressed against the vertical wall is in equilibrium. The minimum coefficient of friction is:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0.4
b
0.2
c
0.5
d
none of these
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Here net driving force= mg-mg2=mg2downwardHence friction will act upward and its magnitude should be f = mg2If the block ‘m’ is stationary the friction between m and the wall should be static.f ≤ flimmg2≤μ.N ⇒ mg2 ≤μ(mg) ⇒ μmin = 12