First slide

Static friction

Question

A block pressed against the vertical wall is in equilibrium. The minimum coefficient of friction is:

Moderate

A

0.4
B

0.2
C

0.5
D

none of these

Solution

Here net driving force
= $mg - \frac{mg}{2} = \frac{mg}{2} downward$
Hence friction will act upward and its magnitude should be $f = \frac{mg}{2}$
If the block ‘m’ is stationary the friction between m and the wall should be static.
$f \leq f_{\lim}$
$\frac{mg}{2} \leq μ . N \Rightarrow \frac{mg}{2} \leq μ (mg) \Rightarrow μ_{\min} = \frac{1}{2}$

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