A block of rectangular size of mass m and area of cross-section A, floats in a liquid of density ρ. If we give a small vertical displacement from equilibrium, it undergoes SHM with time period T, then [AIIMS 2018]
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a
T2∝1ρ
b
T2∝ρ
c
T2∝m-1
d
T2∝1A-2
answer is A.
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Detailed Solution
For a rectangular block, floating in a liquid as shown in the figure below, thenAt equilibrium, mg = Vρg = Alρg⇒ m=Aρlwhere, I = length of part immersed in liquid.When it is given in downward displacement y, restoring force (upward direction) on block is F=-[A(l + y) ρg-mg] =-[A(l+y) ρg-Alρg]=-Aρgyi.e. F∝-y or a∝-y, so it executes SHM.∴ Time period = 2πInertia factorSpring factor T=2πmAρg⇒T2∝mAρor T2∝1ρ