First slide

Conservation of mechanical energy

Question

A block is released from rest from a height of 10m. After travelling through the smooth surface it moves on the rough surface horizontal surface through a length of 6m and climbs on to the other smooth curved surface through a height $h^{'}$ .If $μ = 0.5$ then $h^{'}$ =

Moderate

A

3m
B

4m
C

5m
D

7m

Solution

$\begin{array}{l} W = ΔK . E \\ W_{g} + W_{f} = {KE}_{f} - {KE}_{i} \\ mg (10 - h^{'}) + μ mgscos 180^{\circ} = 0 \\ m g (10 - h^{'}) = 0.5 \times m g \times 6 \\ 10 - h^{'} = 3 \\ h^{'} = 7 m \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App