A block is released from rest from point A on a smooth track, whose cross section in vertical plane is quarter of a circle of radius ‘R’. The value of θ for which the contact force between block and surface is equal to the weight of block is
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a
cos−123
b
cos−113
c
sin−123
d
sin−113
answer is D.
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Detailed Solution
N−mg sinθ=mv2R=mR2gRsinθ; (V2=2gh; h=rsinθ)⇒N=3mgsinθ⇒θ=sin−113 if N = mg