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A block released from rest from the top of a smooth inclined plane of inclination 45° takes time 't' to reach the bottom. The same block released from rest, from top of a rough inclined plane of same inclination, takes time '2t' to reach the bottom, coefficient of friction is:

a
0.75
b
0.5
c
0.25
d
0.4

detailed solution

Correct option is A

acceleration on smooth plane is g sin θ and for rough plane g (sinθ-μcosθ)time is inversely proportional to square root of accelerationtrts=gsinθgsinθ-μcosθ=2 11-μ=4 μ=0.75

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