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A block is released from the top of an inclined plane of inclination θ . Its velocity at the bottom of plane is v. If it slides down a rough inclined plane of the same inclination, its velocity at bottom is v/2. The coefficient of friction is

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a

34cot⁡θ

b

14cot⁡θ

c

14tan⁡θ

d

34tan⁡θ

answer is D.

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Detailed Solution

V=2gLsin⁡θV2=2Lgsin⁡θ−μkcos⁡θsin⁡θ=4sin⁡θ−μkcos⁡θ3sin⁡θ=4μkcos⁡θ⇒μk=34tan⁡θ

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