A block resting on the horizontal surface executes SHM in horizontal plane with amplitude A The frequency of oscillation for which the block just starts to slip is (μ = coefficient of friction, g = gravitational acceleration)
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a
12πμgA
b
14πμgA
c
2πAμg
d
4πAμg
answer is A.
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Detailed Solution
When restoring force will become equal to the frictional force block will start to slip.∴ Restoring force = Friction force⇒ kA=μmg ∵Frestoring =-kx …(i)Now, frequency, f=12πkmFrom Eq. (i), we get f=12πμgA