A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72. If relative density of silver is 10, then tension in the string will be

Let ρS and ρL be the densities of silver and liquid, respectively, and m and V be the mass and volume, respectively, of the silver block. Therefore,Tension in the string = mg - buoyant force⇒ T=ρSVg−ρLVg=ρS−ρLVgAlso, V=mρS∴ T=ρS−ρLρSmg=(10−0.72)×10310×103×4×10=37.12N