A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72 . If relative density of silver is 10 then tension in the string will be

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37.12 N

42 N

73 N

21 N

answer is A.

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Detailed Solution

Tension in the string = mg – buoyant force T=ρsVg−ρLVg =(ρs−ρL)Vg ∴T=(ρs−ρL)mgρs=(10×1000−0.72×1000)4×1010×1000=37.12N ∵V=mρs

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