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Q.

A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72 . If relative density of silver is 10 then tension in the string will be

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a

37.12 N

b

42 N

c

73 N

d

21 N

answer is A.

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Detailed Solution

Tension in the string = mg – buoyant force T=ρsVg−ρLVg  =(ρs−ρL)Vg   ∴T=(ρs−ρL)mgρs=(10×1000−0.72×1000)4×1010×1000=37.12N   ∵V=mρs
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