A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72.If relative density of silver is 10, then tension in the string will be

Let ρS and ρLbe the densities of silver and liquid, respectively, and m and V be the mass and volume, respectively, of the silver block. Therefore,Tension in the string = mg - buoyant force⇒ T=ρSVg−ρLVg=ρS−ρLVg Also, V=mρS∴ T=ρS−ρLρSmg =(10−0.72)×10310×103×4×10=37.12N