Questions
A block slides down a slope of angle θ with constant velocity. It is then projected up with a velocity of 10 , g =10 & θ = 30º. The maximum distance it can go up the plane before coming to stop is
detailed solution
Correct option is B
Since the block slides down the inclined plane with constant velocity, mgsinθ = fk =µk.mgcosθ. During ascent, retardation (a) of the block is a = g(sinθ+μkcosθ)=2gsinθNow, 0 = 102 - 2 x 2gsinθ x s ⇒ S = 1004gsin300 = 5mTalk to our academic expert!
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A body of mass 5 X 10-3 kg is launched upon a rough inclined plane making an angle of 30° with the horizontal. Obtain the coefficient of friction between the body and the plane, if the time of ascent is half of the time of descent.
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