A block slides off a horizontal table 1 m high with a speed of 3 m/s. Find the horizontal distance from the edge of the table at which the block strikes the floor: (Take g = 9.8 m/s2).

In the interval from O to B, ux = 3m/s, uy = 0 m/s.Now, sy = 1 m. As the initial velocity is horizontal, vertical component vy = 0sy=uyt+(1/2)ayt2−1=0(t)+(1/2)(−g)t2⇒t=107ssx=uxt=3107m=ABwhich is the horizontal distance.