First slide

Friction on inclined plane of angle more than angle of repose

Question

A block sliding down on a rough 45⁰ inclined plane has half the velocity it would have been, the inclined plane is smooth. The coefficient of sliding friction between the block and the inclined plane is

Moderate

A

$\frac{1}{4}$
B

$\frac{3}{4}$
C

$\frac{1}{2 \sqrt{2}}$
D

$\frac{1}{\sqrt{2}}$

Solution

v² - u² = 2as
$V_{R} = \sqrt{2 gl (\sin θ - μ_{k} \cos θ)}, V_{S} = \sqrt{2 glsin θ}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App