Questions
A block is suspended by a spring and the elongation produced in the spring is found to be . Then the block is further pulled downward by a distance and released. Then acceleration of the block in its lower most position is
detailed solution
Correct option is A
After release, the block will execute vertical simple harmonic motion about is equilibrium position with amplitude (2x0−x0) i.e. x0 and angular frequency ωHere ω=km and x0=mgk∴ Acceleration at the lower extreme position =ω2x0=(Km) ×mgk=gTalk to our academic expert!
Similar Questions
Two springs of spring constants are joined in series. The effective spring constant of the-combination is given by:
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