A block A with mass 100 kg is resting on another block B of mass 200 kg. As shown in figure a horizontal rope tied to a wall holds it.The coefficient of friction between A and B is 0.2 while coefficient of friction between B and the ground is 0.3. The minimum required force F to start moving B will be

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900 N

100 N

1100 N

1200 N

answer is .

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Detailed Solution

F = fAB+fBG = μABmag+μBG(mA+mB)g = 0.2 × 100 ×10 + 0.3(300)×10 = 200 + 900 = 1100 N

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