A block of wood weights $$10$$ N and is resting on an inclined plank. The coefficient of friction is $$0.7$$. The frictional forces that acts on the block when the plank is $$30$$° inclined with the horizontal is

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Infinity Learn · Accepted Answer

See fig. of the question,From figure, $$R=10cos$$⁡$$30$$∘$$=53Nand$$ μ$$R=10sin$$⁡$$30$$∘$$=5N(Note$$ that μ$$R=0$$⋅$$7$$×$$53=6$$⋅$$062NThis$$ is maximum attainable frictional force. When the inclination of the plank is raised, then $$10$$ $$sin$$ θ increases. The block will remain in rest till $$10$$ $$sin$$ θ attains a value $$6.062$$ N. After that the box will start sliding down the $$plank)$$

A block of wood weights 10 N and is resting on an inclined plank. The coefficient of friction is 0.7. The frictional forces that acts on the block when the plank is 30° inclined with the horizontal is

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