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Q.

A boat is moving directly away from the gun on the shore with speed v1. The gun fires a shell with speed v2 at an angle α and hits the boat. The distance of the boat from the gun at the moment it is fired is

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a

2v2sin⁡αv1cos⁡α−v2g

b

2v1sin⁡αv1cos⁡α−v2g

c

2v2sin⁡αv2cos⁡α−v1g

d

2v2cos⁡αv1sin⁡α−v2g

answer is C.

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Detailed Solution

See fig. (7)For shell to hit the boat, the time taken by the boat to go from B to C with velocity v1 should be equal to the time taken by the shell to go from O to A and then A to C, i.e.,2v2sin⁡αg=TFurther, x+v1T=R=2gv2sin⁡αv2cos⁡α or  x+2gv1v2sin⁡α=2gv2sin⁡αv2cos⁡α or  x=2gv2sin⁡αv2cos⁡α−2gv1v2sin⁡α or  x=2gv2sin⁡αv2cos⁡α−v1
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