A boat is moving directly away from the gun on the shore with speed $$v1$$. The gun fires a shell with speed $$v2$$ at an angle α and hits the boat. The distance of the boat from the gun at the moment it is fired is

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Infinity Learn · Accepted Answer

See fig. $$(7)For$$ shell to hit the boat, the time taken by the boat to go from B to C with velocity $$v1$$ should be equal to the time taken by the shell to go from O to A and then A to C, i.e.,$$2v2sin$$⁡α$$g=TFurther$$, $$x+v1T=R=2gv2sin$$⁡α$$v2cos$$⁡α or  $$x+2gv1v2sin$$⁡α$$=2gv2sin$$⁡α$$v2cos$$⁡α or  $$x=2gv2sin$$⁡α$$v2cos$$⁡α−$$2gv1v2sin$$⁡α or  $$x=2gv2sin$$⁡α$$v2cos$$⁡α−$$v1$$

A boat is moving directly away from the gun on the shore with speed v₁. The gun fires a shell with speed v₂ at an angle α and hits the boat. The distance of the boat from the gun at the moment it is fired is

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A boat is moving directly away from the gun on the shore with speed v1. The gun fires a shell with speed v2 at an angle α and hits the boat. The distance of the boat from the gun at the moment it is fired is

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A boat is moving directly away from the gun on the shore with speed v₁. The gun fires a shell with speed v₂ at an angle α and hits the boat. The distance of the boat from the gun at the moment it is fired is