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Questions  

A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration 'a' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration 'a'(relative to car) vertically. The tension in the string is equal to

a
mg2+a2
b
mg2+a2 - ma
c
mg2+a2+ma
d
m(g+a)

detailed solution

Correct option is

(Force diagram in the frame of the car)Applying Newton's law perpendicular to stringmg sin θ = ma cos θtan θ = agApplying Newton's law along string⇒ T-mg2+a2 = maT = mg2+a2+ma

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Similar Questions

Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:


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