First slide

Vertical circular motion

Question

A bob of mass 100 g tied at the end of a string of length 50 cm is revolved in a vertical circle with a constant speed of 1 ms^–1. When the tension in the string is 0.7N, the angle made by the string with the vertical is (g = 10 ms^–2) .

Easy

A

0⁰
B

90⁰
C

180⁰
D

60⁰

Solution

$\large T = mg\cos \theta + \frac{{m{v^2}}}{r} \Rightarrow 0.7 = \cos \theta + \left( {\frac{{0.1}}{{0.5}}} \right)$
$\large \cos \theta = 0.5 \Rightarrow \theta = {60^0}$

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