The bob of a simple pendulum is displaced from its equilibrium position O to a position Q which is at height h above O and the bob is then released. Assuming the mass of the bob to be m and time period of oscillations to be $$2.0$$ $$sec$$, the tension in the string when the bob passes through O is

Question

Infinity Learn · Accepted Answer

Tension in the string when bob passes through lowest point  $$T=mg+mv2r=mg+mv$$ω      $$($$∵$$v=r$$ω$$)putting$$ $$v=2gh$$ and  ω$$==2$$$$π$$$$T=2$$$$π$$$$2=$$πwe get  $$T=m$$ (g+$$π$$2gh)

The bob of a simple pendulum is displaced from its equilibrium position O to a position Q which is at height h above O and the bob is then released. Assuming the mass of the bob to be m and time period of oscillations to be 2.0 sec, the tension in the string when the bob passes through O is

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