The bob of a simple pendulum is displaced from its equilibrium position O to a position Q which is at height h above O and the bob is then released. Assuming the mass of the bob to be m and time period of oscillations to be $$2.0$$ $$sec$$, the tension in the string when the bob passes through O is

Question

Infinity Learn · Accepted Answer

Tension in the string when bob passes through lowest point T $$=$$ $$mg+mv2r$$ $$=$$ mg $$+$$ mvω $$($$∴ v $$=$$ rω$$)putting$$ v $$=$$ $$2gh$$ and ω $$=$$ $$2$$$$π$$T $$=$$ $$2$$$$π$$$$2$$ $$=$$ πwe get T $$=$$ $$m(g+$$π$$2gh)$$

The bob of a simple pendulum is displaced from its equilibrium position O to a position Q which is at height h above O and the bob is then released. Assuming the mass of the bob to be m and time period of oscillations to be 2.0 sec, the tension in the string when the bob passes through O is

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