Questions
The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is in air. Neglecting frictional force of water and given that the density of the bob is (4/3) ×1000 kg/m3. What relationship between and is true [AIEEE 2004]
detailed solution
Correct option is C
∵ to=2 πlgEffective weight of bob inside water,W'=mg−thrust=Vρg−Vρ'g⇒Vρgeff=V(ρ−ρ')g, where, ρ= Density of bob ⇒geff=1−ρ'ρ g and ρ'= Density of water∴t=2 πlgeff=2 πl(1−ρ'/ρ)g∴tt0=11−ρ'/ρ=11−34 =2 (∵ρ'=103kg/m3 ρ=43×103kg/m3Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests