Q.

The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in air. Neglecting frictional force of water and given that the density of the bob is (43) × 1000 kg/m3. Which relationship between t and t0 is true?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

t = t0

b

t = t02

c

t = 2t0

d

t = 4t0

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

∴ t0 = 2πlgEffective weight of bob inside water,W' = mg - thrrust = Vρg-Vρ`g⇒Vρgeff= V(ρ-ρ1)g, where, ρ = Density of bob⇒geff = (1-ρ'ρ)g and ρ' = Density of water∴ t = 2πlgeff = 2πl(1-ρ'ρ)g∴  tt0 = 11-ρ'ρ = 11-34(∵  ρ' = 103kg/m3 and ρ = 43×103kg/m3) ⇒t = 2 t0
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in air. Neglecting frictional force of water and given that the density of the bob is (43) × 1000 kg/m3. Which relationship between t and t0 is true?