Q.

The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in air. Neglect frictional force of water and consider it is given that the density of the bob is 43×1000kg/m3. The correct relationship between t and t0 is

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a

t=t0

b

t=t02

c

t=2t0

d

t=4t0

answer is C.

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Detailed Solution

Time period for a pendulum is T=2πlg. But if the same pendulum is submerged in water, then the time period isTwat er=T1−dwat erdbob .On substituting the given quantities, we obtain :t=t01−1000×34×1000=2t0
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The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in air. Neglect frictional force of water and consider it is given that the density of the bob is 43×1000kg/m3. The correct relationship between t and t0 is