Q.

The bob of a simple pendulum has a mass of 40 g and a positive charge of 4x10-6 C. It makes 20 oscillation in 45 s. A vertical electric field pointing upward and of magnitude 2.5x104 NC-1 is switched on. How much time, in seconds will it now take to complete 20 oscillations? Take g=10m/s2

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answer is 51.96.

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Detailed Solution

Initially T=2πLg=4520s……………………..(1) Finally T′=2πLg−qEm……………………………….(2) Dividing equation (1) and (2), we getTT′=g−qEmg⇒TT′=1−qEmg=1−4×10−6×2.5×10440×10−3×10 ⇒T′=2.598sFor 20 oscillation, time taken is t = 20x2.598⇒t = 51.96 s
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The bob of a simple pendulum has a mass of 40 g and a positive charge of 4x10-6 C. It makes 20 oscillation in 45 s. A vertical electric field pointing upward and of magnitude 2.5x104 NC-1 is switched on. How much time, in seconds will it now take to complete 20 oscillations? Take g=10m/s2