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A bob of a simple pendulum of mass 40gm with a positive charge 4×10−6C is oscillating with time period 'T1'. An electric field of intensity 20×104 N/c is applied vertically downwards now time period is T2. The value of 'T2'T1 is (g=10 ms−2)

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a

0.16

b

0.64

c

13

d

0.8

answer is C.

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Detailed Solution

T2T1=lg+Eqmlg=gg+Eqm=13

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A bob of a simple pendulum of mass 40gm with a positive charge 4×10−6C is oscillating with time period 'T1'. An electric field of intensity 20×104 N/c is applied vertically downwards now time period is T2. The value of 'T2'T1 is (g=10 ms−2)