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Q.

A bob of a simple pendulum of mass 40 gm with a positive charge 4 x10-6C is oscillating with time period 'T1'. An electric field of intensity 3.6 x 104 N/c is applied vertically upwards now time period is T2.  The value of  T2T1 is (g=10 m/s-2)

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a

0.16

b

0.64

c

1.25

d

0.8

answer is C.

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Detailed Solution

T2T1=gg−a=gg−qEm=106.4=108=1.25  effective g value is g-a
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A bob of a simple pendulum of mass 40 gm with a positive charge 4 x10-6C is oscillating with time period 'T1'. An electric field of intensity 3.6 x 104 N/c is applied vertically upwards now time period is T2.  The value of  T2T1 is (g=10 m/s-2)