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A bob of a simple pendulum of mass 40 gm with a positive charge 4 x $10^{- 6}$ C is oscillating with time period ' $T_{1}$ '. An electric field of intensity 3.6 x $10^{4}$ N/c is applied vertically upwards now time period is $T_{2}$ . The value of $\frac{T_{2}}{T_{1}}$ is (g=10 $m / s^{- 2}$ )

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detailed solution

Correct option is C

T2T1=gg−a=gg−qEm=106.4=108=1.25 effective g value is g-a

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A bob of a simple pendulum of mass 40 gm with a positive charge 4 x10-6C is oscillating with time period 'T1'. An electric field of intensity 3.6 x 104 N/c is applied vertically upwards now time period is T2. The value of T2T1 is (g=10 m/s-2)

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A bob of a simple pendulum of mass 40 gm with a positive charge 4 x $10^{- 6}$ C is oscillating with time period ' $T_{1}$ '. An electric field of intensity 3.6 x $10^{4}$ N/c is applied vertically upwards now time period is $T_{2}$ . The value of $\frac{T_{2}}{T_{1}}$ is (g=10 $m / s^{- 2}$ )