Q.

A body coated black at 600Ksurrounded by atmosphere at 300K has cooling rate r0 the same body at 900K surrounded by the same atmosphere will have cooling rate

Moderate

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4r0

16r0

16r03

81r016

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Stefan's law is E=σT4-T4s, here E is energy radiated by a black body, σ is stefan's constant,T is temperature of the body for given temperature T1,T2 E1E2=T14-Ts4T24-Ts4 substitute the given temperature and cooling rate E1=r0 in the above equationr0E2=6004-30049004-3004⇒r0E2=64-3494-34=1296-816561-81=12156480=316 E2=16r03

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