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Q.

A body cool from 90°C to 70°C in 10 minutes if temperature of surrounding is 20°C find the time taken by body to cool from 60 °C to 30 °C. Assuming Newton's law of cooling isvalid:

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a

10 min

b

24 min

c

36 min

d

8 min

answer is A.

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Detailed Solution

By Newton's law of cooling θ1-θ2t=kθ1+θ22-θ0 ⇒ 90-7010=k90+702-20and 60-30t=k60+302-20 ⇒20t10×30=6025⇒t=36 min.
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