Questions
A body cool from 90°C to 70°C in 10 minutes if temperature of surrounding is 20°C find the time taken by body to cool from 60 °C to 30 °C. Assuming Newton's law of cooling is
valid:
detailed solution
Correct option is A
By Newton's law of cooling θ1-θ2t=kθ1+θ22-θ0 ⇒ 90-7010=k90+702-20and 60-30t=k60+302-20 ⇒20t10×30=6025⇒t=36 min.Similar Questions
Newton's law of cooling is used in the laboratory for determining:
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests